How to get a variable name as a string in PHP
On rare occasions, you may need to retrieve a variable name as a string.
This handy little function retreives the name of the variable:
<?php $my_var = 1; echo var_name ($my_var); ?>
will give 'my_var'.
I started trying to find a solution to this problem, because I needed such a function and because questions about it appeared on several mailing lists and forums:
[PHP] Is there a way to get a variable name as a string?
most people said it was not possible...
Re: [PHP] Is there a way to get a variable name as a string?
From: Rasmus Lerdorf
In PHP it is possible to use a variable if you have its name as a string :
<?php $iVarName = 'MaxSize'; $$iVarName = 10; echo $MaxSize; ?>
But PHP does not natively include a way to get the name of a given variable.
This might be useful in situations where you design a function with a parameter passed by reference and you need to know which variable was sent as a parameter for this function.
The solution :
The following function retreives the variable name from a given variable:
<?php function var_name (&$iVar, &$aDefinedVars) { foreach ($aDefinedVars as $k=>$v) $aDefinedVars_0[$k] = $v; $iVarSave = $iVar; $iVar =!$iVar; $aDiffKeys = array_keys (array_diff_assoc ($aDefinedVars_0, $aDefinedVars)); $iVar = $iVarSave; return $aDiffKeys[0]; } ?>
This function has to be called with a second parameter always set to the result of the function "get_defined_vars()":
<?php var_name($iVar, get_defined_vars()); ?>
How does it work ?
var_name compares the result of the function "get_defined_vars()" before and after modification of the variable whose name we want to find.
The initial set of defined variables passed as a parameter to var_name is first stored in "$aDefinedVars_0" and compared later.
Before modifying the value of the variable, its value is saved in $iVarSave.
$iVar is then changed to something different :
$iVar=!$iVar;
$aDefinedVars keeps track of this modification and can be compare to $aDefinedVars_0 (its initial value). The difference is the variable we modified and we can get its name as a string in the key value of the array record.
The value of the variable is restored to its initial value kept in $iVarSave and the name of the variable is returned.
Example :
The following PHP code shows the function var_name in action:
<?php $v_1 = 1; echo 'var $<b>',var_name ($v_1, get_defined_vars()),'</b> = ',var_dump($v_1),'<br>'; $v_2 = 4; echo 'var $<b>',var_name ($v_2, get_defined_vars()),'</b> = ',var_dump($v_2),'<br>'; $v_3 = 'qwerty'; echo 'var $<b>',var_name ($v_3, get_defined_vars()),'</b> = ',var_dump($v_3),'<br>'; $v_4 = array('aa'=>'11','bb'=>'22',3); echo 'var $<b>',var_name ($v_4, get_defined_vars()),'</b> = ',var_dump($v_4),'<br>'; $v_5 = &$v_2; echo 'var $<b>',var_name ($v_5, get_defined_vars()),'</b> = ',var_dump($v_5),'<br>'; echo 'var $<b>',implode ('</b> / $<b>',var_name ($v_5, get_defined_vars(),true)),'</b> = ',var_dump($v_5),'<br>'; function test() { $v_1 = 'qwerty'; echo 'var $<b>',var_name ($v_1, get_defined_vars()),'</b> = ',var_dump($v_1),'<br> <hr>'; global $v_5; echo 'var $<b>',var_name ($v_5, get_defined_vars()),'</b> = ',var_dump($v_5),'<br> <hr>'; } test(); ?>
var_name can retreive the name of the variable in every case.
Application :
The most direct application of this function is, of course, a "dump" function.
Just call this "dump" function with the variable you want to monitor - do not forget to add the "get_defined_vars()" parameter...
<?php function dump(&$v, &$aDefinedVars) { echo ' <pre>$<b>',implode ('</b> / $<b>',var_name ($v, $aDefinedVars, true)),'</b> = ',print_r($v, true),'</ pre><br> <hr>'; } dump($v_4, get_defined_vars()); ?>
Going further :
The function var_name can be enhanced by adding the parameter $bShowAllRef to show, if set to true, all the references relating to the variable passed as a parameter:
<?php function var_name (&$iVar, &$aDefinedVars, $bShowAllRef=false ) { foreach ($aDefinedVars as $k=>$v) $aDefinedVars_0[$k] = $v; $iVarSave = $iVar; $iVar =!$iVar; $aDiffKeys = array_keys (array_diff_assoc ($aDefinedVars_0, $aDefinedVars)); $iVar = $iVarSave; return ($bShowAllRef? $aDiffKeys: $aDiffKeys[0]); } ?>
That's it ! You can download the function here.
This code is free to use and published under the GPL license.
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Pingback by Cum sa extragi numele unei variabile in PHP? | WorldIT — July 18, 2010 @ 9:19 am
Good Done!
Comment by shafy — August 10, 2010 @ 6:39 am
Works only when there are no class objects - catchable fatal error otherwise
Comment by youlleck — August 12, 2010 @ 7:23 pm
Thanks for sharing.
I trying to find a way to do the samething you have done. I choose to use php extension. then I find your solution. It works great. but the other day I found It can’t work like:
$a = 10;
$b =&$a;
var_name($b, get_defined_vars()); // a instead of a.
Comment by reeze — November 5, 2010 @ 3:36 am
Impressive.
Comment by Yehia — January 11, 2011 @ 12:04 pm
You can do it by converting the variable to a key/value set before passing it to the function.
function varName($theVar) {
$variableName = key($theVar);
$variableValue = $theVar[$variableName];
echo (’The name of the variable used in the function call was ‘.$variableName.”);
echo (’The value of the variable used in the function call was ‘.$variableValue.”);
}
$myVar = ‘abc’;
varName(compact(’myVar’));
Though I don’t recommend creating a reference to a nameless variable, `function varName(&$theVar)` works too.
Since compact() takes the variable name as a string rather than the actual variable, iterating over a list of variable names should be easy.
As to why you would want to do this — don’t ask me but it seems like a lot of people ask the question so here’s my solution.
Comment by EngineerGreg — February 3, 2011 @ 12:33 am
[...] http://mach13.com/how-to-get-a-variable-name-as-a-string-in-php [...]
Pingback by How to get a variable name as a string in PHP - Making stuff work - Tech Notes — February 3, 2011 @ 4:07 am
for comments #6 and #7
First I was excited to see how your solution works.
After some tries, I realized that “compact” is of complete no use here…
You have to enter the variable name as a string parameter… to finally get this variable name…
a simple
function varName($theVarName) { return $theVarName; }
does the same.
Problem is to enter the variable itself as a parameter to get its name.
Comment by admin — February 3, 2011 @ 9:23 am